The frequency of incident light falling on a photosensitive metal plate is doubled, the KE of the emitted photoelectrons is

Let hv0−W0=KIf frequency is doubled, let kinetic energy of photoelectrons be K1.    2hv0−W0=K1⇒    2hv−W0+W0=K1⇒    2K+W0=K1i.e., kinetic energy is more than doubled.