Questions
The frequency of oscillation of a simple pendulum suspended in a satellite that revolve around the earth is
a
1 Hz
b
2 Hz
c
zero
d
infinity
detailed solution
Correct option is C
frequency = zeroT=2πlg in an artificial satellite g=0frequency = 1time period=1Tif g=0 in above equation, T = ∞then frequency = 1∞=0Talk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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