Questions
The frequency of oscillation of the springs shown in fig (4) will be
a
12πkm
b
2πkm
c
12πk1+k2mk1k2
d
12πk1k2k1+k2m
detailed solution
Correct option is D
Here x1=−F/k1 and x2=−F/k2Total extension x=x1+x2=−F1k1+1k2we know that F = - k x k=k1k2k1+k2 Further T=2π(m/k) =2πmk1+k2k1k2 n=1T=12πk1k2mk1+k2Talk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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