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Q.

The frequency of oscillation of the springs shown in fig (4) will be

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a

12πkm

b

2πkm

c

12πk1+k2mk1k2

d

12πk1k2k1+k2m

answer is D.

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Detailed Solution

Here x1=−F/k1  and  x2=−F/k2Total extension x=x1+x2=−F1k1+1k2we know that F = - k  x k=k1k2k1+k2 Further T=2π(m/k) =2πmk1+k2k1k2 n=1T=12πk1k2mk1+k2
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