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Q.

Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is (g=10 m/s2)

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a

2πm/s

b

πm/s

c

1/πm/s

d

1/2πm/s

answer is D.

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Detailed Solution

Mean position of the particle is mg/k distance below the unstretched position of spring. Therefore, amplitude of oscillation is A=mgkω=km=2πf=20π(f=10Hz)mk=1400π2vmax=Aω=g400π2×20π=12πm/s
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