Questions
Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Maximum speed of the particle is (g=10 m/s2)
detailed solution
Correct option is D
Mean position of the particle is mg/k distance below the unstretched position of spring. Therefore, amplitude of oscillation is A=mgkω=km=2πf=20π(f=10Hz)mk=1400π2vmax=Aω=g400π2×20π=12πm/sTalk to our academic expert!
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An ideal spring with spring-constant K is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released with the spring initially unstretched. Then the maximum extension in the spring is
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