Download the app

Questions  

The frequency of a stretched uniform wire under tension is in resonance with the fundamental frequency of a closed tube. If the tension in the wire is increased by 8 N, it is in resonance with the first overtone of the closed tube. The initial tension in the wire is 

a
1 N
b
4 N
c
8 N
d
16 N

detailed solution

Correct option is A

According to problem12LTm=v4L                   …..(i)  and 12LT+8m=3v4L      ..…(ii) Dividing equation (i) and (ii),   TT+8=13⇒T=1 N

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)


phone icon
whats app icon