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Q.

The frequency of a stretched uniform wire under tension is in resonance with the fundamental frequency of a closed tube. If the tension in the wire is increased by 8 N, it is in resonance with the first overtone of the closed tube. The initial tension in the wire is

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a

1 N

b

4 N

c

8 N

d

16 N

answer is A.

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Detailed Solution

According to problem12LTm=v4L …..(i) and 12LT+8m=3v4L ..…(ii) Dividing equation (i) and (ii), TT+8=13⇒T=1 N

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