The frequency of transverse vibrations in a stretched string is 200 Hz. If the tension is increased four times and the length is reduced to one-fourth the original value, the frequency of vibration will be

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25 Hz

200 Hz

400 Hz

1600 Hz

answer is D.

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Detailed Solution

n=12lTm⇒n1n2=l2l1T1T2=1414=18⇒n2=8n1=8×200=1600Hz

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