Questions
The frequency of tuning forks A and B are respectively 3% more and 2% less than the frequency of tuning fork C. When A and B are simultaneously excited, 5 beats per second are produced. Then the frequency of the tuning fork 'A' (in Hz) is
detailed solution
Correct option is C
Let n be the frequency of fork C thennA=n+3n100=103n100 and nB=n−2n100=98100but nA−nB=5⇒5n100=5⇒n=100 Hz∴nA=(103)(100)100=103 HzTalk to our academic expert!
Similar Questions
Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was
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