First slide

Vertical circular motion

Question

A frictionless track ABCDE ends in a circular loop of radius R. A body slides down the track from point A which is at height h=5 cm. Maximum value of R for a body to complete the loop successfully is

Moderate

Solution

$\begin{array}{l} m g h = \frac{1}{2} m v^{2} \\ v = \sqrt{2 g h} = \sqrt{5 g R} \\ ∴ R = \frac{2 h}{5} = \frac{2 \times 5}{5} = 2 c m \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App