A frictionless wire is fixed between A and B inside a sphere of radius R. A small ball slips along the wire. The time taken by the ball to slip from A to B will be
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a
2(R/g)
b
2Rg/gcosâ¡Î¸
c
2Rgcosâ¡Î¸/g]
d
Rg/gcosâ¡Î¸
answer is A.
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Detailed Solution
s=AB=0+12at2Here, a=gcosâ¡Î¸ and AB=2Rcosâ¡Î¸â´ 2Rcosâ¡Î¸=12(gcosâ¡Î¸)t2 or t=2(R/g)