From a circular disc of radius R, a square is cut out with a radius as its diagonal. The centre of mass of remaining portion is at a distance (from the centre)

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R(4π-2)

R(2π)

R(π-2)

R(2π-2)

answer is A.

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Detailed Solution

Here, A1(CC1)=A2(CC2)where, A = area of square and A2 = area of remaining portion.Side of square will be R2∴ CC2=A1A2CC1=(R/2)2πR2-(R/2)2R2=R4π-2

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