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Q.

From a complete ring of mass ‘m’ and radius ‘R’ a 600 sector is removed. The M.I. of the remaining ring about an axis through centre of ring and normal to its plane is

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a

34mR2

b

1112mR2

c

25mR2

d

56mR2

answer is D.

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Detailed Solution

If ‘m’ is the total mass the mass of the removed portion is m6             I=mR2−m6R2             = 56mR2
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