From a complete ring of mass ‘m’ and radius ‘R’ a 600 sector is removed. The M.I. of the remaining ring about an axis through centre of ring and normal to its plane is
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a
34mR2
b
1112mR2
c
25mR2
d
56mR2
answer is D.
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Detailed Solution
If ‘m’ is the total mass the mass of the removed portion is m6 I=mR2−m6R2 = 56mR2