From a conducting sphere of radius R a cavity of radius R/2 is cut out as shown in the figure. At the center of cavity a point charge q is placed then, the potential and field at point P as shown in the figure is
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a
V=q2πε0d, E=q2πε0d2
b
V=q4πε0d, E =q2πε0d2
c
V=q4πε0d, E =q4πε0d2
d
V=q2πε0d, E=q4πε0d2
answer is C.
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Detailed Solution
As it is a conducting sphere total charge remains same .
From a conducting sphere of radius R a cavity of radius R/2 is cut out as shown in the figure. At the center of cavity a point charge q is placed then, the potential and field at point P as shown in the figure is