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Q.

From a cylinder of radius R, a cylinder of radius R/2 is removed, as shown in Fig. Current flowing in the remaining cylinder is I. Then, magnetic field strength is

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a

zero at point A

b

zero at point B

c

μ0I2πRat point A

d

μ0I3πRat point B

answer is D.

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Detailed Solution

Current density j=IπR2-π(R/2)2=4I3πR2Current in the smaller cylinder is Ismall=j.π(R/2)2=I3For A:-  BA=0-μ0(I/3)2π(R/2), For B:- BB=μ0I3πR
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