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From the diagram, it can be calculated that the resistivity of the material of the rod is :

a
5.6 x 10-5 Ω-m
b
3.6 x 10-6 Ω-m
c
1.4 x 10-4 Ω-m
d
2.8 x 10-5 Ω-m

detailed solution

Correct option is D

R=ρlA=VI⇒ρ=AVlI=π0.1 x 10-22 x 401.5 x 3Ω-m=2.8 x 10-5Ω-m

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