First slide

Ohm's law

Question

From the diagram, it can be calculated that the resistivity of the material of the rod is :

Easy

A

$5.6 x 10^{- 5} Ω - m$
B

$3.6 x 10^{- 6} Ω - m$
C

$1.4 x 10^{- 4} Ω - m$
D

$2.8 x 10^{- 5} Ω - m$

Solution

$R = \frac{ρl}{A} = \frac{V}{I}$
$\Rightarrow ρ = \frac{AV}{lI} = \frac{π {(0.1 x 10^{- 2})}^{2} x 40}{1.5 x 3} Ω - m$
$= 2.8 x 10^{- 5} Ω - m$

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