From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre
is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre? [NEET 2016]

Question

Infinity Learn · Accepted Answer

Considering the information given in the question, let us draw the figure.If the above figure is considered, then moment of inertia of disc will be given $$asI=Iremaining$$ $$+I(R/2)$$⇒ Iremaining $$=I$$−$$I(R/2)Putting$$ the values, we $$get=MR22$$−$$M4R222+M4R22=MR22$$−$$MR232+MR216=MR22$$−$$MR2+2MR232=MR22$$−$$3MR232=16MR2$$−$$3MR232Iremaining$$ $$=13MR232$$

From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre
is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre? [NEET 2016]

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From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centreis cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre? [NEET 2016]

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From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre
is cut. What is the moment of inertia of the remaining part of the disc about a perpendicular axis, passing through the centre? [NEET 2016]