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Q.

From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about perpendicular axis, passing through centre?

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a

3 MR232

b

15 MR232

c

13 MR232

d

11MR232

answer is C.

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Detailed Solution

ITotal disc = MR22MRemoved = M4(Mass∝area )Iremoved (about the same perpendicular axis)= M4(R2)22+ M4(R2)2 = 3MR232 Removed disc = Itotal- Iremoved = MR22-332MR2 = 1332MR2

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From a disc of radius R and mass M, a circular hole of diameter R, whose rim passes through the centre is cut. What is the moment of inertia of the remaining part of the disc about perpendicular axis, passing through centre?