From the following data, find the magnitude of Joule's mechanical equivalent of heat. If Cp for hydrogen = 3.409 cal g−1∘C−1,CV for hydrogen = 2.409 cal g−1∘C−1 and molecular weight of hydrogen =2, then the magnitude of joule's mechanical equivalent of heat (in Jcal-1) will be…….

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answer is 4.16.

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Detailed Solution

Here, J = ? Cp=3.409calg−1∘C−1CV=2.409calg−1∘C−1,M=2R=8.31Jmol−1K−1 As, Cp−CV=rJ=RMJ∴ 3.409−2.409=8.312J 1=4.155J J=4.16Jcal−1

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