First slide

Projection Under uniform Acceleration

Question

From a point on the ground and a distance 2 metre from the foot of a vertical wall, a ball is thrown at an angle of 45^o which just clears the top of the wall and afterward strikes the ground at a distance 4 m on the other side. The height of the wall is

Moderate

A

$\frac{2}{3} m$
B

$\frac{3}{4} m$
C

$\frac{1}{3} m$
D

$\frac{4}{3} m$

Solution

$\begin{array}{l} R = \frac{u^{2}}{g} or 6 = \frac{u^{2}}{g} \\ y = xtan θ - \frac{{gx}^{2}}{2 u^{2} \cos^{2} θ} \\ or h = 2 \tan 45^{\circ} - \frac{4}{2 \cos^{2} 45^{\circ}} (\frac{1}{6}) \\ = 2 - \frac{2}{3} = \frac{4}{3} m \end{array}$

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