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Q.

From the surface of a spherical hot black body, energy is radiated at a rate Q watt. If the temperature of the black body is halved and radius is doubled, rate of radiation of energy from its surface will be

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a

Q4

b

Q2

c

4Q

d

2Q

answer is A.

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Detailed Solution

Q=σAT4=σ.4πr2.T4Q1=σ.A1.(T1)4=σ.4π(2r)2.(T2)4∴ Q1Q=4.116⇒Q1=Q4
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