From the top of a tower a body A is thrown up vertically with velocity u and another body B is thrown vertically down with the same velocity u. If vA and vB are their velocities when they reach the ground and tA and tB are their times of flight, then
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a
vA = vB and tA = tB
b
vA > vB and tA > tB
c
vA= vB and tA> tB
d
vA < vB and tA < tB
answer is C.
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Detailed Solution
Taking all upward physical quantities negative and downward physical quantities positive, for stone A, (vA)2 = (-u)2 + 2gh and for stone B, (vB)2 = u2 + 2gh vA = vB stone A goes up, then comes down and then strikes the earth where as after projection stone B goes down and directly strikes the earth therefore tA > tB