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Q.

From the top of a tower a body A is thrown up vertically with velocity u and another body B is thrown vertically down with the same velocity u. If vA and vB are their velocities when they reach the  ground and tA and tB are their times of flight, then

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a

vA = vB and tA = tB

b

vA > vB and tA > tB

c

vA= vB and tA> tB

d

vA < vB and tA < tB

answer is C.

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Detailed Solution

Taking all upward physical quantities negative and downward physical quantities positive, for stone A,  (vA)2 = (-u)2 + 2gh and for stone B, (vB)2 = u2 + 2gh  vA = vB  stone A goes up, then comes down and then strikes the earth where as after projection stone B goes down and  directly  strikes the earth therefore tA > tB
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