Questions
From the top of a tower of height 200 m, a ball A is projected up with speed 10 m s-1 and 2 s later, another ball B is projected vertically down with the same speed. Then
detailed solution
Correct option is A
Total displacement ball A in 2 s,S=ut−12gt2=10×2−12×10×(2)2=0Hence, both A and B will reach the ground simultaneously and strike with the same velocityTalk to our academic expert!
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A body is projected upwards with a velocity u. It passes through a certain point above the ground after time t1. The time after which the body passes through the same point during the return journey is
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