Q.
From the top of a tower of height 200 m, a ball A is projected up with speed 10 m s-1 and 2 s later, another ball B is projected vertically down with the same speed. Then
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a
Both A and B will reach the ground simultaneously
b
Ball A will hit the ground 2 s later than B hitting the ground
c
Both the balls will hit the ground with the same velocity
d
Both will rebound to the same height from the ground, if both have same coefficient of restitution.
answer is A.
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Detailed Solution
Total displacement ball A in 2 s,S=ut−12gt2=10×2−12×10×(2)2=0Hence, both A and B will reach the ground simultaneously and strike with the same velocity
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