From the top of a tower of height 40 m, a ball is projected upwards with a speed of 20 ms-1 at anangle of elevation of 300. The ratio of the total time taken by the ball to hit the ground to the time taken to come back to the same elevation , is (Take, g = 10 ms-2)
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a
2: 1
b
3: 1
c
3: 2
d
1.5 : 1
answer is A.
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Detailed Solution
From sy=uyt+12ayt2, we have -40=20sin30°t-5t2 or t2-2t-8=0Solving this, we get t = 4 sT=2usinθg=2×20×sin30°10=2 s⇒ tT=2:1