From the top of a tower of height 40 m, a ball is projected upwards with a speed of 20 ms-1 at anangle of elevation of 300. The ratio of the total time taken by the ball to hit the ground to the time taken to come back to the same elevation , is (Take, g = 10 ms-2)

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2: 1

3: 1

3: 2

1.5 : 1

answer is A.

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Detailed Solution

From sy=uyt+12ayt2, we have -40=20sin30°t-5t2 or t2-2t-8=0Solving this, we get t = 4 sT=2usinθg=2×20×sin30°10=2 s⇒ tT=2:1

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