First slide

Projection Under uniform Acceleration

Question

From the top of tower of height 20 m, two bodies are simultaneosuly projected one due north and other due west with equal speeds each of 10 m/s. Find the distance between them when they reach ground g =10 m / s²

Moderate

A

Zero
B

20 m
C

10 m
D

$20 \sqrt{2} m$

Solution

Their ranges $U \sqrt{\frac{2 h}{g}}$ are perpendicular and equal so their separation $= \sqrt{R^{2} + R^{2}} = \sqrt{2} R = 20 \sqrt{2} m$ ̣

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