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Q.

From the top of tower of height 80 m, two stones are projected horizontally with velocities 20 ms-1 and 30 ms-1 in opposite directions. Find the distance between both the stones on reaching the ground (in m) Take g=10m/s2

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answer is 200.

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Detailed Solution

80=12×10t2t2=805⇒t=4x1=V1t=20×4=80x2=V2t=30×4=120 Separation x1+x2=80+120=200m
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