First slide

Projectile motion

Question

From the top of tower of height 80 m, two stones are projected horizontally with velocities 20 ms^-1 and 30 ms^-1 in opposite directions. Find the distance between both the stones on reaching the ground (in 10²m). $Take g = 10 {ms}^{- 2}$

Moderate

Solution

$80 = \frac{1}{2} \times 10$
$t^{2} = \frac{80}{5} \Rightarrow t = 4$
$x_{1} = 20 \times 4 = 80$
$x_{2} = 30 \times 4 = 120$
Separation $x_{1} + x_{2} = 80 + 120 = 200 m$

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