From top of a tower, a particle is projected horizontally and another particle is released freely. The time of flight of horizontal projectile is

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same as that of freely falling body

can't be compared

Twice of freely falling

Half of freely falling

answer is A.

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Detailed Solution

for horizontal projected body let initial velocity =u;angle of projection =0 horizontal component of u is=ux=ucos0=u vertical component of u is=uy=usin0=0 time of flight is estimated in vertical direction , applying sy=uyt+12gt2 here sy=h=height of the tower, hence on substituting h=0+12gt2 is obtained for a freely falling body initial velocity u=0 hence ux=0 and uy=0 time of flight is estimated in vertical direction , applying sy=uyt+12gt2 here sy=h=height of the tower, hence on substituting h=0+12gt2 is obtained t is time of flight, and it is same in both the cases

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