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Q.

From the top of tower, a stone is thrown up. It reaches the ground in  t1 second. A second stone thrown down with the same speed reaches the ground in  t2 second. A third stone released from rest reaches the ground in  t3second. Then:

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a

t3=t1+t22

b

t3=t1t2

c

1t3=1t1−1t2

d

t32=t22−t12

answer is B.

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Detailed Solution

-h= ut1-12gt12 h= ut2+12gt22 h= 12gt32
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