Q.

From a tower of height 19.6 m two bodies are simultaneously projected horizontally in opposite directions, with velocities of 1 m/s and 4 m/s, respectively.The horizontal distance between the two bodies when their velocity vectors are perpendicular to each other is

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a

1 m

b

0.5 m

c

2 m

d

4 m

answer is A.

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Detailed Solution

Time after which velocities become perpendicular to each other T=u1u2gThe horizontal distance between the bodies at the instant when the velocity vectors are mutually perpendicular, we have x=v1t+v2t=50.2=1m
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