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From a tower of height 19.6 m two bodies are simultaneously projected horizontally in opposite directions, with velocities of 1 m/s and 4 m/s, respectively.
The horizontal distance between the two bodies when their velocity vectors are perpendicular to each other is

a
1 m
b
0.5 m
c
2 m
d
4 m

detailed solution

Correct option is A

Time after which velocities become perpendicular to each other T=u1u2gThe horizontal distance between the bodies at the instant when the velocity vectors are mutually perpendicular, we have x=v1t+v2t=50.2=1m

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