From what height should an ice block at – 20°C be freely released so that 84 % of its mechanical energy is converted into heat and it just melts as it reaches the ground(g = 10 ms– 2specific heat of ice is 0.5cal/gm/°C and latent heat of fusion of ice is 80 cal/gm)
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a
4.05 m
b
450m
c
4.5 m
d
45 km
answer is D.
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Detailed Solution
mgh×84100=[m×0.5×[0−(−20)]+m×80]×4.2×103→h = 45 km.