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A full-wave p–n diode rectifier uses a load resistor of $1500 Ω$ . No filter is used. The forward bias resistance of the diode is $10 Ω$ . The efficiency of the rectifier is

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detailed solution

Correct option is C

Efficiency η=0.812×RLRL+Rf×100 =0.812×15001500+10×100 =80.66%

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A full-wave p–n diode rectifier uses a load resistor of 1500Ω . No filter is used. The forward bias resistance of the diode is 10 Ω . The efficiency of the rectifier is

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A full-wave p–n diode rectifier uses a load resistor of $1500 Ω$ . No filter is used. The forward bias resistance of the diode is $10 Ω$ . The efficiency of the rectifier is