A fully charged capacitor C with initial charge Q is connected to a coil of self inductances L at t = 0. The time at which the energy is stored equally between the, electric and the magnetic fields is :
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a
πLC
b
π4LC
c
2πLC
d
LC
answer is B.
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Detailed Solution
energy across the capacitor becomes half when energy across inductor and capacitor are equal i.e Q24CQ24C= Q2cos2ωt2C 12= cosωt 1LCt=π4 t= π4LC