Questions
The function represents
a
A periodic but not simple harmonic motion
b
A simple harmonic motion with a period
c
A simple harmonic motion with a period half that of
d
A simple harmonic motion with a period twice that of
detailed solution
Correct option is C
x=sin2ωt=12×2sin2ωt So the particle is executing SHM with amplitude 1/2 and frequency i.e. . The equilibrium position of the particle is at x = 1/2.Now time period of x = cos ωt is .So option (3) is right.Talk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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