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Q.

The function sin2  Ï‰trepresents

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a

a simple harmonic motion with period 2π/ω

b

a simple harmonic motion with a period Ï€/ω

c

a periodic, but not a simple harmonic motion with a period of 2 Ï€/ω

d

a periodic, but not a simple harmonic motion with a period of  Ï€/ω

answer is B.

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Detailed Solution

The equation y=sin2⁡ωt t = 12×2sin2 Ï‰t =12(1- sin 2ωt) = 12 - 12sin 2ωt   Time period ,T=2π2ω = Ï€Ï‰
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