The function of time representing a simple harmonic motion with a period of πω is :

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sinωt+cosωt

3cosπ4−2ωt

sin22ωt

cosωt+cos2ωt+cos3ωt

answer is B.

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Detailed Solution

Check for option (2)y=3cos⁡π4−2ωt ⇒y=3cos⁡(2ωt−π/4) It is SHM Time Period=T=2π2ω=πω

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