Questions
Fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l. The value of lc is (m)
detailed solution
Correct option is B
Fundamental frequency of open pipe = first overtone of closed pipe ⇒v2l0=3v4lc⇒lc=3×2×0.54=0.75mTalk to our academic expert!
Similar Questions
A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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