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Q.

A fuse F1 is connected across an ideal source of variable voltage and the voltage is increased gradually. The fuse blows out just when the reading of the voltmeter and ammeter reaches 1.0 V and 1.0 A respectively (see figure (i)). The experiment is repeated with another fuse F2 and the reading of the voltmeter and ammeter when it blows out is 2.4 V and 1.2 A respectively. The ammeter & voltmeter are idealNow these two fuses are connected in parallel as shown in figure(ii). Voltage is increased gradually. The addition of reading of the ammeter and voltmeter just before when any one of the fuses blows out is

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answer is 3.5.

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Detailed Solution

Consider fuse to be ideal ohmic element.R1=V1i1=11=1Ω R2=V2i2=2.41.2=2Ωi1=iR2R1+R2 1=i(2)1+2 i=32A=1.5Ai2=iR1R1+R2 1.2=i(1)1+2 i=3.6ATake i=1.5A because if we take greater than 1.5A then  fuse will blows out
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