In the fusion reaction $$12H+12H$$⟶$$23He+01n$$, the masses of deuteron, helium and neutron expressed in amu are $$2.015$$, $$3.017$$ and $$1.009$$, respectively. If $$1g$$ of deuterium undergoes complete fusion, then the amount of total energy released is $$9$$ x $$10n$$ kJ. Find the value of n.

Question

In the fusion reaction  $$12H+12H$$⟶$$23He+01n$$, the masses of deuteron, helium and neutron expressed in amu are $$2.015$$, $$3.017$$ and $$1.009$$, respectively. If $$1g$$ of deuterium undergoes complete fusion, then the amount of total energy released is $$9$$ x $$10n$$ kJ. Find the value of n.

Infinity Learn · Accepted Answer

Δ$$m=2(2.015)$$−(3.017+1.009)=0.004amu$$∴  Energy released $$=(30.004$$×$$931.5)MeV$$ $$=3.726MeVEnergy$$ released per deuteron                        $$=3.7262=1.863MeVNumber$$ of deuterons in $$1g$$                         $$=6.02$$×$$10232=3.01$$×$$1023$$∴Energy released per g of deuterium $$fusion=3.01$$×$$1023$$×$$1.863=5.6$$×$$1023MeV$$≈$$9.0$$×$$1010J$$≃$$9$$×$$109kJ$$≃$$9$$×$$10nkJ$$ $$(given) ∴$$n=9$$

Nuclear reactions - Nuclei

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Nuclear reactions - Nuclei

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In the fusion reaction 12H+12H⟶23He+01n, the masses of deuteron, helium and neutron expressed in amu are 2.015, 3.017 and 1.009, respectively. If 1g of deuterium undergoes complete fusion, then the amount of total energy released is 9 x 10n kJ. Find the value of n.

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