A 15 g ball is shot from a spring gun whose spring has a force constant of 600 N/m. The spring is compressed by 5 cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m/s2)

For getting horizontal range, there must be some inclination of spring with ground to project ball.⇒Rmax=u2g                                       …..(i)But K.E. acquired by ball  = P.E. of spring gun ⇒12mu2=12kx2⇒u2=kx2m             …..(ii)From equation (i) and (ii) Rmax=kx2mg=600×(5×10−2)215×10−3×10=10m.