A $$15$$ g ball is shot from a spring gun whose spring has a force constant of $$600$$ $$N/m$$. The spring is compressed by $$5$$ cm. The greatest possible horizontal range of the ball for this compression is (g$$ $$=$$ $$10$$ $$m/s2)

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Infinity Learn · Accepted Answer

For getting horizontal range, there must be some inclination of spring with ground to project ball.⇒$$Rmax=u2g$$                                       …..(i)But$$ K.E. acquired by ball  $$=$$ P.E. of spring gun ⇒$$12mu2=12kx2$$⇒$$u2=kx2m$$             …..$$(ii)From$$ equation $$(i) and (ii) $$Rmax=kx2mg=600$$×$$(5$$×$$10$$−$$2)215$$×$$10$$−$$3$$×$$10=10m$$.

A 15 g ball is shot from a spring gun whose spring has a force constant of 600 N/m. The spring is compressed by 5 cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m/s²)

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A 15 g ball is shot from a spring gun whose spring has a force constant of 600 N/m. The spring is compressed by 5 cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m/s2)

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A 15 g ball is shot from a spring gun whose spring has a force constant of 600 N/m. The spring is compressed by 5 cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m/s²)