20 g of boiling water is poured into an ice-cold brass vessel (specific heat 0.1 cal/g C0) of mass 100 g. The resulting temperature is:
66.66°C
6.66°C
0.66°C
50°C
Let resulting temperature be 0 then by principle of calorimetry 20×1×(100-θ)=100×0.1×(θ-0) ⇒ θ =66.66oC