A $$50$$ g bullet moving with velocity $$10$$ $$m/s$$ strikes a block of mass $$950$$ g at rest and gets embedded in it. The loss in kinetic energy will be (in$$ %$$)

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Initial K.E. of system $$=$$ K.E. of the bullet $$=$$ $$12mBvB2By$$ the law of conservation of linear momentum $$mBvB+0=msys$$.×vsys.⇒vsys.$$=mBvBmsys$$.$$=50$$×$$1050+950=0.5$$ m​$$/$$​sFractional loss in K.E.  $$=$$  $$12mBvB2$$−$$12msys$$.$$vsys.212mBvB2By$$ substituting  $$mB=50$$×$$10$$−$$3kg$$, $$vB=10$$ m​$$/$$​s                      msys.$$=1kg$$, $$vs=0.5$$ m​$$/$$​s we get Fractional loss $$=$$  $$95100$$   ∴ Percentage loss $$=$$ $$95$$%

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A 50 g bullet moving with velocity 10 m/s strikes a block of mass 950 g at rest and gets embedded in it. The loss in kinetic energy will be (in %)

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