First slide

Second law

Question

A 150 g cricket ball, moving horizontally at 20 m/s was hit straight back to the bowler at 12 m/s. If contact with the bat lasted for (1/25) sec, the average force exerted by the bat on the ball is

Moderate

A

100 N
B

120 N
C

150 N
D

200 N

Solution

$F = \frac{150 \times 10^{- 3} [20 - (- 12)]}{1 / 25} N = 120 N$

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