Questions
A 150 g cricket ball, moving horizontally at 20 m/s was hit straight back to the bowler at 12 m/s. If contact with the bat lasted for (1/25) sec, the average force exerted by the bat on the ball is
detailed solution
Correct option is B
F=150×10−3[20−(−12)]1/25N=120 NTalk to our academic expert!
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