1 g of ice at 0°C is converted into steam at 100°C. The amount of heat required to do so is:

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80 cal

536 cal

616 cal

0.716 kcal

answer is D.

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Detailed Solution

ice0oC1 g→80 calwater0oC1 g→100 calwater100o C1 g→540 calsteam100oC1 g

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