60 g of ice at 00C is mixed with 60 g of steam at 1000C. At thermal eqilibrium, the mixture contains

mLS = Q1Q1 = 60 x 540 = 32400 → steam to water at 1000CmLi + msΔt = Q2Q2 = 60 x 80 + 60 x 1 x 100 = 10800 → ice to water at 1000CSince Q1 > Q2, a part of the steam is condensed.If x gm of steam is converted into water at 1000C  so the final mixture contains (60 - 20)gm of steam is 40gm of steam and (60 + 20) gm of water i.e. 80gm of water.