10 g of ice cubes at 00C are released in a tumbler (water equivalent 55 g) at 400C. Assuming that negligible heat is taken from the surroundings, the temperature of water in the tumbler becomes nearly (Take, L = 80 cal/g)

Let T be the temperature when thermal equilibrium has reached.Heat gained by ice to be converted to water at 00C=mL+m×c×(T−0)=10×80+10×1×THeat lost by tumbler and its contents = 55 x (40 - T)Using principle of calorimetry, heat gained = heat lost10×80+10×1×T=55×(40−T)⇒ 65T=2200−800=1400⇒ T=140065≈21.5∘C≈22∘C