First slide

Accuracy; precision of instruments and errors in measurements

Question

5.74 g of a substance occupies $1.2 c m^{3} .$ Keeping the significant figure in view, its density is given by

Moderate

A

$4.8 g c m^{- 3}$
B

$1.5 g c m^{- 3}$
C

$2.1 g c m^{- 3}$
D

$9.2 g c m^{- 3}$

Solution

There are 3 significant figures in the measured mass whereas there are only 2 significant figures in the measured volume. Hence, the density should be expressed to only 2
significant figures.
$∵ D e n s i t y = \frac{M a s s}{V o l u m e}$
$∴ D e n s i t y = \frac{5.74}{1.2} g c m^{- 3} = 4.8 g c m^{- 3}$

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