5.74 g of a substance occupies 1.2 cm3. Keeping the significant figure in view, its density is given by
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a
4.8 g cm−3
b
1.5 g cm−3
c
2.1 g cm−3
d
9.2 g cm−3
answer is A.
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Detailed Solution
There are 3 significant figures in the measured mass whereas there are only 2 significant figures in the measured volume. Hence, the density should be expressed to only 2significant figures. ∵ Density=MassVolume∴ Density=5.741.2g cm−3=4.8 g cm−3