10 g of water at 70°C is mixed with 5 g of water at 30°C. Find the temperature of the mixture in equilibrium.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 36.67.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let t° C be the temperature of the mixture. From energy conservation,Heat given by 10 g of water = Heat taken by 5 g of water or m1Cwater Δt1=m2Cwater Δt2∴(10)(70−t)=5(t−30)∴t=36.67∘C