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10 g of water at 70°C is mixed with 5 g of water at 30°C. Find the temperature of the mixture in equilibrium.

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answer is 36.67.

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Detailed Solution

Let t° C be the temperature of the mixture. From energy conservation,Heat given by 10 g of water = Heat taken by 5 g of water or m1Cwater Δt1=m2Cwater Δt2∴(10)(70−t)=5(t−30)∴t=36.67∘C

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10 g of water at 70°C is mixed with 5 g of water at 30°C. Find the temperature of the mixture in equilibrium.