Calorimetry

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By Expert Faculty of Sri Chaitanya

Question

10 g of water at 70°C is mixed with 5 g of water at 30°C. Find the temperature of the mixture in equilibrium.

Moderate

Solution

Let t° C be the temperature of the mixture. From energy conservation,
Heat given by 10 g of water = Heat taken by 5 g of water
$\begin{array}{l} or m_{1} C_{water} |{Δt}_{1}| = m_{2} C_{water} |{Δt}_{2}| \\ ∴ (10) (70 - t) = 5 (t - 30) \\ ∴ t = 36 {.67}^{\circ} C \end{array}$

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