100g of water is heated from 300C to 500C. Ignoring the slight expansion of the water, the change in its internal energy is (specific heat of water is 4148 J/kg/K):
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a
8.4 kJ
b
84 kJ
c
2.1kJ
d
4.2 kJ
answer is A.
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Detailed Solution
ΔQ=msΔT=100×10−3×4.184×20=8.4×103 ΔQ=8.4kJ , ΔW=0From the first law of thermodynamics, ΔQ=ΔU+ΔWThen, U=8.4kJ