1 g of water, of volume 1cm3at 100°C, is converted into steam at same temperature under normal atmospheric pressure (1×105 Pa).The volume of steam formed equals 1671cm3. If the specific latent heat of vaporisation of water is 2256 J/g, the change in internal energy is,

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2256 J

2423 J

2089 J

167 J

answer is C.

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Detailed Solution

ΔQ=2256×1=2256 J ΔW=PVsteam -Vwater =1×105[1671-1]×10-6=1670×105×10-6=167 JBy first law of thermodynamics: As ΔQ=ΔU+ΔW2256=ΔU+167ΔU=2089 J

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