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Questions  

Galileo writes that for angle of projection of a projectile at angle (450 - θ) and (450 + θ), the horizontal ranges described by the projectile are in the ratio of (if θ  450)

a
2 : 1
b
1 : 2
c
1 : 1
d
2 : 3

detailed solution

Correct option is C

For angle (450 - θ), R=u2sin90°-2θg=u2cos2θgFor angle (450 + θ), R=u2sin90°+2θg=u2cos2θgThus, ratio becomes 1 : 1.

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