Q.
Galileo writes that for angles of projection of a projectile at angles (450+θ) and (450-θ), the horizontal ranges described by the projectile are in the ratio of (if θ>450)
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
2 : 1
b
1 : 2
c
1 : 1
d
2 : 3
answer is C.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
For a projectile launched with velocity u at an angle θ, the horizontal range is given byR = u2sin2 θg(i) for θ1 = 450-θ R1 = u2sin(900-2θ)g = u2gcos2θ(ii) For θ2 = 450 + θR2=u2sin(900+2θ)g=u2gcos2θ
Watch 3-min video & get full concept clarity